.5x^2+4x+7.5=0

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Solution for .5x^2+4x+7.5=0 equation: 



.5x^2+4x+7.5=0

a = .5; b = 4; c = +7.5;
Δ = b2-4ac
Δ = 42-4·.5·7.5
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-1}{2*.5}=\frac{-5}{1}
=-5
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+1}{2*.5}=\frac{-3}{1}
=-3
$

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